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Question Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. Input: 38 Output: 2 Explanation: The process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. Solution.h //Hearder #include #include class Solution { private : int input_num; public: int addDigits(int num); int inputData(); void outputData(int num); }; Solution.cpp ..